If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1000x^2-100x-21=0
a = 1000; b = -100; c = -21;
Δ = b2-4ac
Δ = -1002-4·1000·(-21)
Δ = 94000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{94000}=\sqrt{400*235}=\sqrt{400}*\sqrt{235}=20\sqrt{235}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-20\sqrt{235}}{2*1000}=\frac{100-20\sqrt{235}}{2000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+20\sqrt{235}}{2*1000}=\frac{100+20\sqrt{235}}{2000} $
| 4(v-7)=9v-3 | | 8u+36=6(u+4) | | 8u+36=6(6+4) | | -6=-8+2u | | ((2x+3)/4)-((3x-5)/3)=2 | | 4(2y+1)=57 | | x1√3=x-1√2 | | 4.9x^2-3.75x+0.2=0 | | 6x^2-5*x+6=0 | | 5/21=7/x | | 2x(2x+1)=-6 | | 4x-2(1-x)=2(3x-2 | | 10-7b=-5(2b+9)+36 | | 5-2x(2x+1)=-6 | | -3/2=5/3x-7/9 | | 1/2x-5=1/3x+7 | | 5x/3-2=x/2+8 | | 7=3x/2+4 | | x/3+9=4 | | 3y+11=4(2y-1) | | (x^2-x)^2=x^2 | | 2y-2=4y+6 | | 11-6(m-5)=13+2(m-9) | | 440,000=x(30-0.4x) | | 2(x+1.4)=6.2 | | R=x(30-0.4x) | | 4x-10x=8-3(2x+1) | | -5=x^2+6x | | 8+5m/5=21 | | 2x÷3+1÷5=x÷3+4÷5 | | 3(x-4)/2=3(x+2)/8 | | 67*x/60=60•(x+12)*60 |